[quote author="gyraf"]
But why 3:1+1+1 and not sqrt(3):1+1+1
Because the power transfer from the microphone will, in case of 3:1+1+1, be 1:1 overall. The sqrt(3):1+1+1 (=1.7:3) will load the mic with too low a Z.
Downside of the 3:1+1+1 is that you loose 9-10dB of signal level - but this is unavoidable..
Jakob E.[/quote]
It's obvious I'm goofing here.
So let's write down what went on in my head so that we can pinpoint where I made my error :wink:
I didn't consider power but just impedances. I assumed a 200 Ohm source & say 2k mic-pre loading (for one single micpre).
In order to maintain that 2kOhm load for the mic in case of three of such mic-pre's connected I figured that each micpre should now look like 3 times that 2kOhm.
So impedance-ratio 3, and turns-ratio the sqrt of that.
Let's assume three separate TX's inserted, each with its primary connected to the mic & its sec to it's respect. mic-pre input. Each mic-pre now looks like 6kOhm to the mic, and since we have three of them in // we get 2kOhm.
Next step is to merge those three TXs into one TX with
turns-ratio sqrt(3):1+1+1 ('impedance-ratio' '3:1+1+1'). Still the same, correct ?
Where did I make the thinking-error ? Did we confuse
turns &
impedance perhaps ?
Thanks,
Peter