equation for working out tube circuit impedance

skal1 said:

abbey road d enfer said:

I = voltage at one end minus voltage at other end divided by resistance.
Current in R3 & R4 is (210 - 65)/47k = 3.08mA; this is the small-signal current (Vg = -0.5V - high bias - no compression)
Under high-signal (Vg = -30V - low bias - mucho compression) (290 - 285)/47k = 0.1mA
When resistance is expressed in ohms, the result is in Amps; when expressed in kilo-ohms, the result is in milliAmps.

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so if i did not have the idle voltage which 65v {no compression) on the schem how would i work out the voltage drop across R3 AND R4 , would the formula be

voltage drop =current *ohms ?

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