Niketouille
Well-known member
I am looking for info concerning the inductor. The value are on the schematic but I have no idea how to find the esr value.
Cheers
Cheers
gyraf said:Does not compute. ESR is for capacitors...?
With pleasure sir, that's exactly what I need. Do you have original units ?drask said:Do you want the resistance of each tap?
With pleasure sir, that's exactly what I need. Do you have original units ?drask said:Do you want the resistance of each tap?
This loss's full descriptor is the series resistance.Niketouille said:But also for inductor. The wire lenght introduce lossesgyraf said:Does not compute. ESR is for capacitors...?
these appear as a parallels resistor. I'm fully aware that some textbooks use the delta-y transformation to lump the series resistance and the equivalent loss resistance into one single element, but this just doesn't give a proper description over the whole operating range.and if the inductor has a core it also introduces losses
Yes and no. In a proper design, the losses influence the overall BW (I deliberately don't use the term "Q" because it is improper in a biquadratic equation) at the second-order. The series resistance is the main factor there. Again, in a properly designed product, the final BW would be governed by an external resistor, i.e. the inductor's intrinsic Q would be larger than what's needed for the intended performance. That's the case with the TG12412, where each inductor has a separate series resistor (R10, R17 & R19), which could be adjusted in case of manufacturing changes; in addition some of the taps (most of them in fact) have additional resistors (R1-9 & R11-16).Those losses are what limits the Q factor in a passive eq.
You just tell him to make the DCR lower than 200r. [/quote] then you will adjust the value of the series resistance for expected performance.Niketouille said:Thank you very much for those precises explanations.
It seems that in the case of the tg12414 the serie resistor of each taps are so low they have only use one resistor to adjust the BW/Q.
That leads me to another question, how do I choose my inductor characteristic in such a design ? The wire lengh seems not to be a factor anymore as long as the serie resistor is low compare to 200ohms.
Actually the real question is, what do I tell Sir Chrion so he can make me some inductor for this project ?
I suspect it is in respect to a shelving EQ...can you put more context? La phrase complète, si possible...Also in the manual I am reading "the frequency of half lift or cut is 500Hz". Does someone know what "half lift/cut" mean ?
Niketouille said:3.5.5 Bass Control
This provides a flat position and five 2dB steps of lift or cut. Although it is called a bass control, the frequency of half lift or cut is actually 500Hz. The frequency response obtained at the various settings is shown in Drawing No. 375. The circuit is described in 12.2. Since the circuit has no output capacitor, a 6.8μF capacitor is provided externally with 150kΩ to the 0 V line to prevent a large plop when the fader is inserted.
A shelving EQ doesn't have a definite "center frequency", like a bell EQ has, so very often the boost/cut is defined with a frequency, close to where the response goes asymptotic. You will see LF EQ +18dB at 100Hz, and the actual graph will do that but it will be about +3dB at 1kHz, +10 at 250Hz and +20 at 30Hz. Defining half lift makes this frequency independant of the amount of boost/cut. E.g. for 6dB boost, the half lift will be the +3dB point, for 12dB, it will be the +6dB point. Very British.Niketouille said:3.5.5 Bass Control
This provides a flat position and five 2dB steps of lift or cut. Although it is called a bass control, the frequency of half lift or cut is actually 500Hz. The frequency response obtained at the various settings is shown in Drawing No. 375. The circuit is described in 12.2. Since the circuit has no output capacitor, a 6.8μF capacitor is provided externally with 150kΩ to the 0 V line to prevent a large plop when the fader is inserted.
Can you post a graph?Niketouille said:So what does it could means as it is not a shelving eq ?
On the LF control, the BL, MED and SH positions are bells and the LOW position has only LR in circuit, which makes it a shelf; the HIGH position has an RC circuit, making ita shelf, but with a very low turnover frequency, meaning that everything is boost or cut, except LF.Niketouille said:My bad, there is a resistor in serie with the inductor and no capacitor... so it is shelving I guess. It all makes sense now.
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