In this article about the mixing network:
http://www.forsselltech.com/summing buss.htm
Fred says ("resistor" is the summing resistor for each channel):
"With such a resistor in place for each channel, the impedance seen by any single channel is now the value of its summing resistor plus the parallel value of all the channels hanging on the buss.
If we use 1k ohm resistors for these resistors in a 10 channel mixer we would have a parallel source impedance of 100 ohms (1k/10= 100). This is the buss source impedance. Each channel will now see its summing resistor in series with the buss source impedance. That means each channel will see 1k (the summing resistor) plus 100 ohms (the source impedance of the buss) or 1.1k ohms as its load. Using larger value summing resistors will increase the load impedance seen by each channel."
To my eye, looking at the schem, a single channel should see its summing resistor in series with the parallel of all the other channel resistors, not all the channels in parallel. So the impedance seen by any channel should be 1k + (1k/9)...
Where's my mistake?
Does the output impedance of the other channels play a role or I can ignore it as its value is much lower than that of the summing resistor?
Many thanks,
Frank
http://www.forsselltech.com/summing buss.htm
Fred says ("resistor" is the summing resistor for each channel):
"With such a resistor in place for each channel, the impedance seen by any single channel is now the value of its summing resistor plus the parallel value of all the channels hanging on the buss.
If we use 1k ohm resistors for these resistors in a 10 channel mixer we would have a parallel source impedance of 100 ohms (1k/10= 100). This is the buss source impedance. Each channel will now see its summing resistor in series with the buss source impedance. That means each channel will see 1k (the summing resistor) plus 100 ohms (the source impedance of the buss) or 1.1k ohms as its load. Using larger value summing resistors will increase the load impedance seen by each channel."
To my eye, looking at the schem, a single channel should see its summing resistor in series with the parallel of all the other channel resistors, not all the channels in parallel. So the impedance seen by any channel should be 1k + (1k/9)...
Where's my mistake?
Does the output impedance of the other channels play a role or I can ignore it as its value is much lower than that of the summing resistor?
Many thanks,
Frank