Hey folks,
I'm building my own U47 and there is a 1780 Ohm wire wound resistor that looks like that:
Is it possible to do it on my own?
As base i have cut a the inner cardbox of a role of duct tape. Fits good!
As wire i would use this: http://www.spulen.com/widerstandsdraht-0-032mm-1650-ohm-meter-klasse-bis-1ppm-k.html
As I reckon in the worst case 1510 Ohm =1000mm
so 1 Ohm = 0,66 mm
1780 Ohm = 1178 mm
the cadbox has an hight of 13 mm and a lenght of 65 mm. -8 mm for the connection = 57 mm.
as the wire is wound around this carbox i got ~ 26 mm for one winding.
1178mm/26mm =45 windings
So there would be 8 windings per 10 mm.
I reckon that over this 1780 Ohm resistor will be a Voltage drop of 69 Volt.
From this i recon 0,039 Ampere flowing.
So there will be an load of 2,67 Watts.
2,67 Watts with a 0,034 qmm resistance wire?
I dont have a clue!
Cheers,
Zottel.
I'm building my own U47 and there is a 1780 Ohm wire wound resistor that looks like that:
Is it possible to do it on my own?
As base i have cut a the inner cardbox of a role of duct tape. Fits good!
As wire i would use this: http://www.spulen.com/widerstandsdraht-0-032mm-1650-ohm-meter-klasse-bis-1ppm-k.html
As I reckon in the worst case 1510 Ohm =1000mm
so 1 Ohm = 0,66 mm
1780 Ohm = 1178 mm
the cadbox has an hight of 13 mm and a lenght of 65 mm. -8 mm for the connection = 57 mm.
as the wire is wound around this carbox i got ~ 26 mm for one winding.
1178mm/26mm =45 windings
So there would be 8 windings per 10 mm.
I reckon that over this 1780 Ohm resistor will be a Voltage drop of 69 Volt.
From this i recon 0,039 Ampere flowing.
So there will be an load of 2,67 Watts.
2,67 Watts with a 0,034 qmm resistance wire?
I dont have a clue!
Cheers,
Zottel.