Good morning,
literally spent the whole day yesterday with trying to get things solved unfortunately with no results but some knowledge gained.
I fed symmetrical external audio via a 10u caps to each side the b+ of the mu tubes et voila I had super clean audio on the output which tells me that the distortions happens on the first stage. This rises some questions about the origin of the distortion that I would appreciate your thoughts about.
Image:
https://www.dropbox.com/s/pzz4psn2b4wp4p2/IMG_9450.jpg?dl=01) Lowering the plate resistor from 12k5 to 1k5 also lowers the maximum swing of the anode voltage, right?
May this be a reason for distortion to occur?
2) When I lower the input by about 12dB distortion seems to disappear. This is btw. the same amount of gain I lost on the interstage when lowering the plate resistors.
3) I compensated for the gain loss by changing the input pad to a 1k - 2k - 1k where it was 2k5 - 320 - 2k5 before. So yep I might be feeding too much voltage to the grids. But I can only change this when having more gain in the first stage. This is because of the overall noise that would be amplified in later stages leading to new troubles
What I think of now is:
4) Changing the interstage to a 1:1 (15k) Edcor XSM (now its WSM) which has more Henries as some forum research revealed.
->
https://groupdiy.com/index.php?topic=55122.0This would allow me to have a larger plate resistor. This giving me more gain allowing for a stiffer pad on the input and more voltage swing on the anode.
Does this sound logical to you gentleman? Any advice is highly appreciated.
(ALERT! Tube newbie might talk nonsense

)
Btw. is there anyone with a tube tester in Berlin?
Thank you,
Falk
Edit: One more questions and some math:
Z = impedance
XL = inductive reactance
R = resistance
When considering the following:
Z = sqrt(R^2 + X^2)
X = sqrt (Z^2 - R^2)
for high impedance transformers R is much smaller than Z so we can almost ignore R.
In this case we can consider Z = X
From this point:
L = XL / ( 2 × π × f ) where XL is the inductive reactance given with 15k
L (60Hz) = 39H
L = XL / ( 2 × π × f ) where XL is the inductive reactance given with 10k
L (60Hz) = 26H
The thing is: How I came up with lowering the plate resistor was due to my simulation which uses 8H. I am not sure if I ever tried the original values actually. When I assume 20H (still a bit conservative) the simulation works great with original values. Maybe I really should not question what the engineers invented without computers. That makes me feel even more stupid.