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Close, but no. Assuming that's the 2217-40 meter, spec sheet says "Input impedance Voltage DC 10 MΩ". Considering the oscillator is supposed to supply that voltage into (in theory) infinite-ohms, it might still be too low.


Where did that "40m" figure come from, by the way? Small "m" is the SI prefix for "milli", ie. 1000x SMALLER than the reference unit. Capital "M" is the prefix for "mega", ie. one million times GREATER than the reference unit.


If you had something like a 100Meg resistor at hand (ideally not more loose than +/-10% tolerance), you could probe the voltage with that in series (the "top" resistor in the resulting divider; your meter's input impedance would then become the "bottom" resistor), and then multiply the reading by 11x to get (close to) the real voltage there.


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