Making linear potentiometer

[iprovlek]

Hi guys!

Is it possible to make 10k and 22k linear potentiometer with 1x12 lorlin switch!?

Please if someone know how to do it, I would be grateful....


Thanks

 

[ruffrecords]

Yes, a linear pot switch is quite easy. If you have a 12 way switch just divide the total resistance by 11 and connect this value between each adjacent pair of contacts. So for your 22K example, the value you need is 2K.

Cheers

Ian

 

[iprovlek]

Thanks a lot Ian!

Can you explain more closely!?

If I go with 1x12 lorlin switch, first resistor is 2k if I understand!?

 

[ln76d]

Each one should be 2k. 22k/11=2k so you need eleven 2k resistors

 

[iprovlek]

Thanks a lot Ln76d!

I will try it....