That's actually a respectable output transformer (Carvin probably sourced only one for guitar and bass amps).
Here's what's up with cap sizes. Capacitors are often used as coupling capacitors: a capacitor in series with the signal, with a resistor on the output side. This stops DC from passing, but lets the signal pass, above a particular frequency. That frequency is deternined by this formula:
f = 1 / (2 x pi x R X C)
where f is the cutoff frequency in Hz (the frequency at which response is down 3dB), R is in ohms and C is in farads, and pi is in your face ... er, well, you know what pi is.
C37 on the schematic is a good example. It's equal to .01µF, which is the same as 10^-8 farads. The following resistor is 1 megohm, or 10^6 ohms. Plugging the numbers into the formula, we get:
f = 1/ (2 x 3.14159 x 1,000,000 x 10^-8) = 15.9Hz.
That's a reasonable cutoff frequency for a guitar amp, but maybe you should extend it a bit for a bass. It's considered a good rule of thumb that you want response to extend to 1/10 the lowest frequency to be handled. In the case of a 4-string bass that's about 42 Hz.
You can turn the equation around to figure out what capacitor to use:
C = 1 / (2 x pi x f x R)
Same units; for a cutoff frequency of 4.2Hz,
C = 1 / (2 x 3.14159 x 4.2 x 1,000,000) = 3.79 x 10^-8. That's the same as .0379µF; the closest standard value would be .039µF.
The bypass capacitors on the cathodes of the tubes follow the same formula; do the arithmetic and see what their cutoff frequencies are -- oh, here's something that will help you:
f = 1,000,000 / (2 x pi x R x C)
In this version of the formula, f is still in Hz and R is still in ohms but C is now in µF, a much more manageable unit. And pi is still...
Note that all these formulas compute how deep the bass goes, not whether there's "more bass". Admittedly, that's a subtle distinction.
Peace,
Paul