Proper termination resistors

[Val_r]

In the schem above:

TR1 has prims and secs wired in series, with C.T. to gnd, input and output are balanced, and is rated 600R:40K.

What are the proper values for R1, R2 to get the 600R at the input, 20K or 10K?

Thanks.

Val.

:roll:

 

[Boswell]

For impedance calculation purposes, ignore the centre-taps. They are just a way of balancing the signals with respect to ground. So for an impedance ratio of 600R:40K (turns ratio of 1:8.16), you need 40K across the secondary to see 600R across the primary. That means R1 and R2 would each be 20K in your case.

 

[CJ]

You need to mark that xfmr diagram so we know which side is which.

Maybe the resistors are on the 600 side?

In that case, you can handle the math.

 

[Guest]

20K each.

 

[Val_r]

[quote author="CJ"]You need to mark that xfmr diagram so we know which side is which.

Maybe the resistors are on the 600 side?

In that case, you can handle the math.[/quote]

The primary is on the left, and is rated 600 ohms, sec. (on the right) is rated 40K, turns ratio is 1:8.165 .

Correct value for R1 and R2 appears to be 20K, which would give a total of 40K to let see on the whole secondary. Right?