Question on interconnectivity -10, line level, +4 etc...

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I have a multitrack recorder that I want to feed from one of DIY mic pres

Now the multitrack I have has unbalanced inputs and outputs at something called -10db?
What does the fact it is unbalanced have to do with this -10db?
Isn't the difference between balanced and unbalanced just a signal and an inverted signal going down the cable?

Second question is more to do with DIY console design...
Taking the unbalanced multiitrack outputs into the DIY modules (EQ/Compressor) - are we going to have level problems again?

Third question
DO any of you take the multritrack outputs into the DIY micpres
And if so - how and more importantly WHY?
I imagine the how is done by putting a line level input on the DIY Mic Pre
 
[quote author="uk03878"] I have a multitrack recorder that I want to feed from one of DIY mic pres

Now the multitrack I have has unbalanced inputs and outputs at something called -10db?
What does the fact it is unbalanced have to do with this -10db?
Isn't the difference between balanced and unbalanced just a signal and an inverted signal going down the cable?[/quote]

Yes. db measurements are always in reference to some voltage. With balanced systems, (+4db U, 0dbU=0.775 Volts. Unbalanced (-10dbV, 0dbV=1 Volt. Why are there two standards? I don't believe that there is any other reason than because designers choose to do so...



[/b]
 
re using mic pre, I think you may be referring to the practice of using a mic pre as the mix amp after a passive summing bus where the (high quality) mic pre is used because it is a low impedance/high gain stage..

for the multitrack outs, it depends how hot they are, otherwise it would be better to control the level with the mixer gain before sending to your units on an insert/aux.
 
Thanks guys
Jonathan - lullabies from around the world - you old softy!!

One further question...
But what if I didn;t use a mixer? and my outputs where -10 unbalanced from the multitrack?
Eventually the signals would be summed by a DIY summing box and therefore the proposed signal chain would be something like this...

mic - mic pre - multitrack

multitrack - patchbay
patchbay - compressor - patchbay (optional)
patchbay - EQ - patchbay (optional)
patchbay - effects - patchbay (optional)
patchbay - summing box - stereo master
 
I don't see a problem with that setup - apart from being unable to change levels except by using the makeup gains etc on individual processors - I assume you're trying to avoid using a mixer. You might be alright if the level from the tape is too hot - you could attenuate passively somewhere (more DIY), but what if it's not hot enough for, say, your compressor input. Alternatively, can you tweak the output stage of your tape machine - are they top-accessible?

Me an old softy? Music for children is the new rock'n'roll, it actually feels a lot more creative to work on than most of the 'serious' music I've done. Did you hear the mp3s?
 
> has unbalanced inputs and outputs at something called -10db?
What does the fact it is unbalanced have to do with this -10db?


You can design an interface any way you like.

We normally spec as: impedance (matching, or source/load); level; and unbalanced/ balanced/ floating.

Telephone convention runs to 100-900Ω, balanced, -10dBm talk, +10dBm shout.

Broadcast convention is typically 150/600Ω, balanced, +8dBm on program VU (implying +18dBm to +24dBm on peaks)

Recording industry convention starts from broadcast custom but typically runs +4dBm program VU for a bit more headroom on the same gear.

With the rise of chips, it was easy to make good audio but hard to reach the old broadcast conventions. +24dBm peaks is a 0.25 Watt power level. All the voltage, currents, powers, and impedances are just past the limits of common chips.

But these conventions derive from long outside lines. Inside a small studio, there is no reason to be gushing 1/4Watt in the wires, nor any reason to be working to 100-900Ω loads. 100ft/30m of cable is 3,000pFd and will drop to about 3,000Ω at the top of the audio band, very different from driving thousands of feet of cable inside a major network broadcast facility or studio-transmitter link.

The hi-fi guys faced the same problem: full Pro-Audio interface specs are expensive, add excess stages and distortions, and solve problems you don't have in a 1-room audio system. Hi-fi interfaces are 0.1V to 1.0V, source impedance 1K or less, load 10K or more, and always unbalanced (ignoring recent fads for balanced operation). Voltage levels were poorly specified until cassette decks all grew Dolby: the standard Dolby chip runs 0.316 Volts at Dolby Zero level (roughly zero VU or the 3%THD point of early cassette tape) and most deck makers just buffered this to the jacks. You can have peak signals 14dB to 16dB above Dolby reference level. In CD playback they set levels so digital full scale comes out about 2VRMS, which with typical program material on a VU-speed meter will read about 0.3V average.

-10dB relative to 1 Volt is 0.316 volts. If you measure program with a slow VU meter, the loud parts are about 0.3V. If you use a peak meter, a full power sine is 2V (2.8V peak).

TASCAM revolutionized low-price multi-track work with this -10dB standard. All line interfaces unbalanced, under-1K output impedance but should not be loaded with less than 10K load. Eliminates a small power amp at every output and a transformer at all inputs and outputs. You can do everything with 741-class chips. (With +/-15V supplies, a 741 can do more than 2.8V peak; but it will be straining to make 10V peaks in the treble. The 2.8V peaks pass easily through modest chips.)

The "-10dB" is referenced to 1 Volt; the "dBm" standard is a power spec and makes no sense in a hi-Z load system.

But this raises a problem: what is the difference between "-10dB" and "+4dBm, 600Ω"? In voltage, it is 12dB (not 14dB) or 1:4, because 0dBm is 0.775V in 600Ω and 0.775V is about -2dB from 1V.

> I have a multitrack recorder that I want to feed from one of DIY mic pres

Mike preamps come in ALL sizes and flavors. However nearly any of then can feed a TASCAM-type "-10dB". The ones with a single op-amp output are inherently TASCAM-like. "Pro" +4dBm 600Ω outputs will easily drive -10dV re:1V into 10KΩ, just don't use as much gain. If they are balanced, take one wire to the unbalanced hot, the other to ground. If that distorts (many balanced outputs don't like one side grounded) let the other hot leg float.

The converse is not always true. While many "600Ω" inputs are really 10K and have enough reserve gain to take -10dB signals well, some passive EQs and some tube-boxes with high-ratio input transformers really are 600Ω. According to TASCAM spec, this is too low. 741-class chips will strain (though often work OK). 5532-class chips will drive 600Ω without much strain.

> DO any of you take the multritrack outputs into the DIY micpres

WHY, when you already have a line-level, would you go back into a mike preamp? Mike preamps solve the specific problem that mikes have weak outputs. When faced with a weak source, the first thing you do is bring it up to some convenient level (line level) where it can't be easily contaminated with noise. Then you never go near mike level again: that would double your noise. As you say: "WHY?"

OK, in the real-world we often do go through a mike preamp. Sometimes we have a weak "line level" source, like a faint recording on a wimpy consumer tape deck. And sometimes we avoid the cost of balanced line inputs (which are not essential in small-studio work), then when we need a balanced line input we have to pad the line down to mike-level and use our excellent mike input.

Recently there is a fad for using mike preamps as distortion boxes. Distortion is useful. But it should not be confused with the precision job of amplification. And I don't believe distortion should be applied in tracking, on the one and only recording of that performance. This isn't direct-to-disk! Capture it clean, take a day off to rest your ears, then apply distortion as an editing/mixing effect same as reverb or EQ. That way if you screw-up you can go back to the clean master and try again with more subtlety. It is too easy to use too much reverb fuzz EQ: it sounds good one day on one speaker and wretched when you sober-up or try it in the car.
 
[quote author="PRR"]Broadcast convention is typically 150/600Ω, balanced, +8dBm on program VU (implying +18dBm to +24dBm on peaks)[/quote]

A nitpicking broadcast engineer speaks: :green:

That info is a little out-of-date. Broadcast convention nowadays is +4dBU balanced, low-Z source, high-Z load. There is the odd piece of 600-ohm gear still being made here and there, and some "legacy" +8dBM equipment (such as the Ampex VTRs we just got rid of recently). But by and large, broadcast facilities now follow the same convention as the recording industry.

My broadcast experience has been mostly in less-than-state-of-the-art facilities, so there's usually a mixture of old and new gear just to keep things confusing :wink: And even our new-ish Sigma 16x16 audio-video routers need 600-ohm terminations on the outputs if you don't want the signal to be 6dB hot :roll:
 
[quote author="ebartlet"]
Yes. db measurements are always in reference to some voltage. With balanced systems, (+4db U, 0dbU=0.775 Volts. Unbalanced (-10dbV, 0dbV=1 Volt. Why are there two standards? I don't believe that there is any other reason than because designers choose to do so...
[/b][/quote]
Well... I wouldn't say that there was a reason or justification neccessarily - but there is a bit of an explanation, as PRR has pointed out. You can quite easily calculate accurately the difference between the 'standards' - if that's what they really are - by rearranging the formula for calculating voltage differences in dB so that it works the other way around. The formula says that the dB value = 20*Log (V1/Vref). So basically, we have to antilog the two values we've got into their correct voltages, and then log them again.

So for the -10dBV we get V/1 = 10^(-10/20) = 0.316V

And for the +4dBU we get V/0.775 = 10^(+4/20) = 0.775*10^(+4/20) = 1.2282V

Finally, 20*Log (0.316/1.2282) = 11.792dB difference between -10dBV and +4dBV

And so, as PRR very nearly says, it's about 12dB...

*postscript*
It occurred to me afterwards that there's a much simpler (and slightly more accurate, but who cares at this level) way of arriving at the answer - and that's to say
20*Log (ref dBV/ref dBU) = 20Log (1/0.775) = 2.214 dB and simply subtract this from 14... = 11.786dB
 
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