Viitalahde
Wellknown member
This morning's thoughts:
I started wondering about the basic attack/release time constant circuit used in many compressors.
The basic circuit: R1 defines how C1 is charged, and R2 defines the discharge. Attack & release.
Now, without doing any maths (yet), I am wondering if there could be a sonic difference between these two circuits?
A) R1 & R2 are large, C1 = small
b) R1 & R2 are small, C1 = large
Both cases designed for same mathematical charge & discharge. Case A is obviously a high impedance circuit where B is a lowimpedance circuit with high capacitance.
If both circuits act the same way on the paper, I suppose the driver before this could make a difference? LowZ with high capacitance.. tough to drive.
From somewhere I remember the Fairchild 670 has a beefy (8 watts or so) sidechain driver?
I quess the ultimate question is: how do the designers end up with the R/C combinations in sidechains? They design the rectifier & driver and calculate around that, then listen & tweak?
I started wondering about the basic attack/release time constant circuit used in many compressors.
Code:
R1
IN >/\/\/\/oo> OUT
 
 /
C1  \ R2
 /
 \
 
 
ooo




The basic circuit: R1 defines how C1 is charged, and R2 defines the discharge. Attack & release.
Now, without doing any maths (yet), I am wondering if there could be a sonic difference between these two circuits?
A) R1 & R2 are large, C1 = small
b) R1 & R2 are small, C1 = large
Both cases designed for same mathematical charge & discharge. Case A is obviously a high impedance circuit where B is a lowimpedance circuit with high capacitance.
If both circuits act the same way on the paper, I suppose the driver before this could make a difference? LowZ with high capacitance.. tough to drive.
From somewhere I remember the Fairchild 670 has a beefy (8 watts or so) sidechain driver?
I quess the ultimate question is: how do the designers end up with the R/C combinations in sidechains? They design the rectifier & driver and calculate around that, then listen & tweak?