You can theoretically use +16V if you don't exceed maximum voltage or
current ratings on any component. However, transistors will bias
differently, so "tone" will change. This is fuzz, so apropriate "tone" is
highly subjective matter. What are you planning to use this
thing for, guitars or general purpose mangler? Depending on this,
you can drop first and last transistor stages, and replace them with
something "transparent" (or whatever). Improving dynamic range of
fuzzbox seem like oximoron to me. And improving "sound" of fuzzbox
is way beyond subjective. Generaly, you can't drive single suply circuit
with bipolar suply, without changing circuit.
Just quick transistor tutorial: your first concern here is how will transistors
bias when you change suply. So you are examining conditions after suply
is turned on and everithing is settled, but there is no signal in sight.
First thing to do is to asume capacitors are ideal and you replace them
with open circuit. Now first three stages look the same.
So you will check just first stage.
You are left with suply (Vcc), ground, Q1 ,R2, R3, R4 and R5. Erase
everything else.
Now you asume few things: Q1 is in forward active mode (you need this
for amplification)so colector and base are sucking curent, and that
current flows out of emiter, hfe (or beta, whatever you call it) is large
enough so that you asume Ic=Ie and Vbe is number you choose freely
between 0.6 and 0.7 volts. This asumptions will ease your life and
parameter tolerance will **** you up much more than these asumptions.
Emiter voltage is:
Ve=Ic*R4
Base voltage is:
Vb=Ve+Vbe=Ic*R4+Vbe
Now asume that base current is much (more than ten times) smaller
than currents through R2 and R3, so you can neglect it.
In that case colector voltage is:
Vc=R3*Vb/R2+Vb=(R2+R3)*(Ic*R4+Vbe)/R2
Finaly, R5 current is equal R3 current plus colector current, so you
write this:
(Vcc-Vc)/R5=Ic+(Vc-Vb)/R3=Ic+Vb/R2
You replace Vc and Vb with equations derivated above. You get
big ugly equation, where only unknown thing is Ic. You fiddle
with that equation till you get Ic on one side and everything else on other.
So you will have equation how Ic (thus bias point) depends on
components and suply voltage.
When you find Ic for some particular values, just check
if your asumption that base current is much smaller than current trough R3
is still valid. If not, back to square one.
Hope spelling errors and bad english didnt made this completly unreadable
cheerz
urosh