> recommended load resistance for push pull 6v6 6f6 tubes is 10000 plate to plate.
Close enough, for Vg2 similar to Vp, for maximum output at tolerable distortion.
> as low as 5000 ohms primary for example the Collins 26w limiter.
Push-pull 6F6 can do 10 Watts! The limiter does not have to be a Power Amp. 1 Watt, +30dBm, into the line is very ample. It was customary to use an amp significantly bigger than the required power, so it would work down in its low-THD zone. 4% at 11 Watts might be 1% at 1 Watt or 0.5% at +28dBm. Also it would not go SPLATT if somehow +31dBm was passed through it. Also 6F6 was VERY widely used, in-stock everywhere, and as-cheap-as any smaller power tube.
So for the limiter, MAX Power Output is not a concern, some mis-loading is very acceptable.
Electrons do NOT like to jump off solid matter and go through empty space. Tubes are high impedance. Low-Z tubes cost more, need more drive, more heater, etc.
Transformers choke and leak. Hi-Z windings have much more bandwidth trouble than low-Z windings. A low-Z winding is easier to design for wide bandwidth. It also uses fatter copper, less cost to hammer-down thin, less turns, less breakage, so faster winding.
And Standard Parts often trump custom parts. Unless using teeny-triodes like 6SN7, 5KCT was a very standard big-line-output part.
> for most purposes? .... more headroom and less current?
What are you building? A line-amp which works easy and "clean"? Or a LOUD amp which you will beat to the MAX? In easy audio working, current is essentially idle current. Set this high enough so current hardly changes at the highest level you really need. P-P 6F6 with 5K load will make over 5 Watts or +37dBm. In modern studios you never want over +20dBm, 1/10th Watt. You could actually work near 35V and 10mA, squeeze almost +20dBm out. Working at 200V and 60mA, it will do way-way over +20dBm while "idling".
If you gonna BEAT the beast, as in a guitar amp with a drummer, the current demand MUST be estimated from loadline. If the tube were ample (6F6 aint), then for P-P Pentode take the p-p load impedance, divide by 2, and assume the amp will suck B+ like a resistor that size. 5K/2= 2.5K, so with big 6L6 etc at 250V it could suck 250V/2K5= 100mA at MAX output.