Please school me on this, as there are mythical posts around here explaining the theory but I can't find the whole explanation in one place. Hopefully this will help other noobs like myself
This is my understanding of the "usual suspect" 6AL5 sidechain/detector circuit, a-la Sta-level, Rs124, Alter 436, UA 175/6 etc.
1. Blocking caps take only AC from the plates of the output tubes
2. the 6AL5 rectifier produces a DC signal that will be applied to the grids of our vari-mu tubes. More signal on the cathodes means more DC output to the grids and therefore more compression. ***Why are voltage readings on a meter actually lower with faster speeds, not enough time to charge back up? ***
3. The threshold network sets the DC operating point of the 6AL5 (220k resistors off cathodes). More DC means we need more signal from our output section to overcome the bias and begin compression. Less DC on the cathodes here means every little sound from the output tubes will be passed through to the time circuit, and we will get a higher ratio (more compression) for the louder parts.
4. Before our signal reaches the grids of the input tubes, this DC signal passes through the time circuit
4. The attack resistor controls the rate at which the capacitor charges
5. The capacitor controls the amount of voltage on the grids of the vari-mu tubes, A larger capacitor will take larger to charge, meaning slower attack AND release
6. The resistor in parallel to the cap determines the rate at which the voltage is drained out of the cap, called release
7. The signal is fed into the grids of our vari-mu tubes, the higher the DC voltage from our sidechain, the more compression (gain reduction) we will get.
What I don't understand is how the AC and DC interact in the sidechain. It's DC coming out of the 6AL5, but this DC swings from a steady 25ish volts down to 6ish in proportion to the output tube signal on the cathodes, making it AC right? Why wouldn't the SC cap dump all the AC swing right away, and the Release resistor dump the DC immediately, resulting in 0V coming out of the side-chain at any given time? With 0 volts coming out of the detector wouldn't it result in no compression?
If shrinking all the time values results in distortion, would adding a second 6al5 in parallel with the first offer more current to be able to refill the cap fast enough to lower distortion
?
This is my understanding of the "usual suspect" 6AL5 sidechain/detector circuit, a-la Sta-level, Rs124, Alter 436, UA 175/6 etc.
1. Blocking caps take only AC from the plates of the output tubes
2. the 6AL5 rectifier produces a DC signal that will be applied to the grids of our vari-mu tubes. More signal on the cathodes means more DC output to the grids and therefore more compression. ***Why are voltage readings on a meter actually lower with faster speeds, not enough time to charge back up? ***
3. The threshold network sets the DC operating point of the 6AL5 (220k resistors off cathodes). More DC means we need more signal from our output section to overcome the bias and begin compression. Less DC on the cathodes here means every little sound from the output tubes will be passed through to the time circuit, and we will get a higher ratio (more compression) for the louder parts.
4. Before our signal reaches the grids of the input tubes, this DC signal passes through the time circuit
4. The attack resistor controls the rate at which the capacitor charges
5. The capacitor controls the amount of voltage on the grids of the vari-mu tubes, A larger capacitor will take larger to charge, meaning slower attack AND release
6. The resistor in parallel to the cap determines the rate at which the voltage is drained out of the cap, called release
7. The signal is fed into the grids of our vari-mu tubes, the higher the DC voltage from our sidechain, the more compression (gain reduction) we will get.
What I don't understand is how the AC and DC interact in the sidechain. It's DC coming out of the 6AL5, but this DC swings from a steady 25ish volts down to 6ish in proportion to the output tube signal on the cathodes, making it AC right? Why wouldn't the SC cap dump all the AC swing right away, and the Release resistor dump the DC immediately, resulting in 0V coming out of the side-chain at any given time? With 0 volts coming out of the detector wouldn't it result in no compression?
If shrinking all the time values results in distortion, would adding a second 6al5 in parallel with the first offer more current to be able to refill the cap fast enough to lower distortion
