lowatt
New member
Hi,
I have a question about how to calculate frequency in relation to the potentiometer resistance. The Calrec PQ11549 EQ has a dual-gang reverse log pot in each band circuit. What formula would be used to derive the frequency at a particular resistance setting? Let's take for example the High-Mid. I guess something that involves a pi*R*C?
Thanks in advance![Smile :) :)](data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7)
![PQ1549-HighMid.png PQ1549-HighMid.png](https://cdn.imagearchive.com/groupdiy/data/attachments/77/77774-68bbd5dcb47df563b6bf5c2dea51f013.jpg)
![HigMidFrq.png HigMidFrq.png](https://cdn.imagearchive.com/groupdiy/data/attachments/77/77775-b457012c2bf3a574fd524862aa8ad3dc.jpg)
I have a question about how to calculate frequency in relation to the potentiometer resistance. The Calrec PQ11549 EQ has a dual-gang reverse log pot in each band circuit. What formula would be used to derive the frequency at a particular resistance setting? Let's take for example the High-Mid. I guess something that involves a pi*R*C?
Thanks in advance
![PQ1549-HighMid.png PQ1549-HighMid.png](https://cdn.imagearchive.com/groupdiy/data/attachments/77/77774-68bbd5dcb47df563b6bf5c2dea51f013.jpg)
![HigMidFrq.png HigMidFrq.png](https://cdn.imagearchive.com/groupdiy/data/attachments/77/77775-b457012c2bf3a574fd524862aa8ad3dc.jpg)