bcarso
Well-known member
Thomas, the LED is used because it has a relatively low impedance, for example compared to the equivalent resistor with the same voltage drop and current, and because it has a good match the the temperature coefficient of a Si Q base-emitter junction.
Because of that low Z, changing the current to the LED doesn't change the voltage that much, and therefore doesn't change the current out of the transistors that much. Jung was looking for a way to make the current constant and relatively independent of supply voltage. A PTC thermistor might help a bit, depending on its temperature coefficient at that operating point, but it's not clear how without detailed data on the thermistor. Also, if it changes too much the LED starts to get higher impedance and the current source may not work as well.
The suggestion to let the current sources have a negative tempco by using two or more diodes in series in place of the LEDs is maybe a bit more likely to be successful. This is after the Rs at the emitters of the driver transistors are adjusted upward to turn on the output stage properly, since that's when having only 2Vbe of tempco probably isn't enough to prevent thermal runaway.
You could also consider putting diodes in series with each driver transistor emitter, to provide two more Vbe's and their associated tempcos. BTW, PRR has just guessed at the roughly four Vbe's I believe---there's no guarantee there . This is a complex output stage. I did some sims myself but the program I use takes temperature into account with extreme reluctance.
Because of that low Z, changing the current to the LED doesn't change the voltage that much, and therefore doesn't change the current out of the transistors that much. Jung was looking for a way to make the current constant and relatively independent of supply voltage. A PTC thermistor might help a bit, depending on its temperature coefficient at that operating point, but it's not clear how without detailed data on the thermistor. Also, if it changes too much the LED starts to get higher impedance and the current source may not work as well.
The suggestion to let the current sources have a negative tempco by using two or more diodes in series in place of the LEDs is maybe a bit more likely to be successful. This is after the Rs at the emitters of the driver transistors are adjusted upward to turn on the output stage properly, since that's when having only 2Vbe of tempco probably isn't enough to prevent thermal runaway.
You could also consider putting diodes in series with each driver transistor emitter, to provide two more Vbe's and their associated tempcos. BTW, PRR has just guessed at the roughly four Vbe's I believe---there's no guarantee there . This is a complex output stage. I did some sims myself but the program I use takes temperature into account with extreme reluctance.