Hi everybody
I am currently working on a pcb for the Neumann PEV-c equalizer.
Most of the pcb is ready, but couldn't find information regarding the output transformer - probably a custom made Haufe. So I am looking for a suitable transformer off the shelf.
My idea was to use Lundahl LL1517 or LL1524, mainly because they are available on the used market for less than a brand new transformer.
https://www.lundahltransformers.com/wp-content/uploads/datasheets/1524.pdf
https://www.lundahltransformers.com/wp-content/uploads/datasheets/1517.pdf
Lundahl datasheets say that the transformers have to be used in a mixed feedback configuration, to provide a negative impedance to the transformer.
From what I can understand looking at the PEV-c schematic, this doesn't seem to be the case.
This circuit is made of two OA10 opamps in push pull configuration. The OA10 datasheet states 250 ohm output impedance (f=100Hz, open loop)
Lundahl datasheets say the optimum source impedance is minus 14 ohm, minus 18 ohm.
I expect the transformer needs to be properly chosen with respect to the impedance of the output stage, but on the Lundahl datasheet displays the turns ratio only, and a negative source impedance is recommended.
How can I figure out, first of all the exact impedance of the output stage, and then the correct transformer able to perform well with such source impedance ?
Also, I guess the transformer should best be connected 1:2 to maximise output level, but that would means a higher impedance is reflected at the primary ? So this has to be taken into account as well ?
Really hope someone can shed light on this subject.
Thanks in advance for any reply.
I am currently working on a pcb for the Neumann PEV-c equalizer.
Most of the pcb is ready, but couldn't find information regarding the output transformer - probably a custom made Haufe. So I am looking for a suitable transformer off the shelf.
My idea was to use Lundahl LL1517 or LL1524, mainly because they are available on the used market for less than a brand new transformer.
https://www.lundahltransformers.com/wp-content/uploads/datasheets/1524.pdf
https://www.lundahltransformers.com/wp-content/uploads/datasheets/1517.pdf
Lundahl datasheets say that the transformers have to be used in a mixed feedback configuration, to provide a negative impedance to the transformer.
From what I can understand looking at the PEV-c schematic, this doesn't seem to be the case.
This circuit is made of two OA10 opamps in push pull configuration. The OA10 datasheet states 250 ohm output impedance (f=100Hz, open loop)
Lundahl datasheets say the optimum source impedance is minus 14 ohm, minus 18 ohm.
I expect the transformer needs to be properly chosen with respect to the impedance of the output stage, but on the Lundahl datasheet displays the turns ratio only, and a negative source impedance is recommended.
How can I figure out, first of all the exact impedance of the output stage, and then the correct transformer able to perform well with such source impedance ?
Also, I guess the transformer should best be connected 1:2 to maximise output level, but that would means a higher impedance is reflected at the primary ? So this has to be taken into account as well ?
Really hope someone can shed light on this subject.
Thanks in advance for any reply.