So, halve the load impedance when a second output tube is put in parallel. If one tube is not conducting, would I calculate the output impedance based on a single output tube?
I'm building a guitar amp based on one of the AX84 projects. I decided to do a switchable parallel single ended ouput. The idea is to have the second tube switched on and off by switching the screen from DC to ground. I'm laying out components and was deciding on switching transofmer taps via switch or simply plugging into a different jack. I then realized that I'd been assuming that a second output tube would only require a different load if conducting but I really don't know for sure.
I'm building a guitar amp based on one of the AX84 projects. I decided to do a switchable parallel single ended ouput. The idea is to have the second tube switched on and off by switching the screen from DC to ground. I'm laying out components and was deciding on switching transofmer taps via switch or simply plugging into a different jack. I then realized that I'd been assuming that a second output tube would only require a different load if conducting but I really don't know for sure.