pucho812
Well-known member
So I got asked if there was a way to passively sum without need of makeup gain for the following a RND 5059. They literally want to take stereo 1 and stereo 2 outputs and sum them down to a single output. No volume control, just a bare bones summing of 2 stereo signals into 1. The purpose is to be able to use both busses at mix down to a single output in the analog domain. Then they can compressor or eq that before going back into the DAW.
Unfortunately on the RND website they don't list the output Ω
So I know for my inputs 2 X 5K resistors per channel. Which if my math is right will give me a buss Ω of 10K. If I divide that by the number of channels 2 I get 5K
Using math to get me a shut resistor Rsh = (Rbus * Z)/(Rbus - Z) and an expected output of 600Ω, I get RSH = (3000000 * 5000) / (5000 - 600) which is roughly 680Ω. I am thinking for the shut resistor, I would just stick a 1 K trim pot in there and go to town.
Unfortunately on the RND website they don't list the output Ω
So I know for my inputs 2 X 5K resistors per channel. Which if my math is right will give me a buss Ω of 10K. If I divide that by the number of channels 2 I get 5K
Using math to get me a shut resistor Rsh = (Rbus * Z)/(Rbus - Z) and an expected output of 600Ω, I get RSH = (3000000 * 5000) / (5000 - 600) which is roughly 680Ω. I am thinking for the shut resistor, I would just stick a 1 K trim pot in there and go to town.
