Hi all...
According to my attached picture I would like to ask how a passive attenuator on the input transformer primary affect the input impedance.
In A there is just a pic of transformer and a resistor and if I understand it correctly the impedance in will be 1k ohm in that specific case if nothing else is interfering.
I am not sure if Ohm's law is useful to calculate the value of the attenuator... making it a parallel resistance. If so the value of the primary impedance won't go higher that the lowest of resistances. ( I am not sure if this is how it works with impedances ... ohm's law is understood)
If it works then you should be able to use higher values of total resistance in the attenuator since the Zin is 1k and the total value of Zin will not exceed 1k???
If NOT working... How does the total value of an attenuator affect the impedance in? I am also curious about the shown attenuators how they affect the impedance since I have seen them her e and there.
I am just brainstorming with myself here so please be gentle
Best regards
/John
According to my attached picture I would like to ask how a passive attenuator on the input transformer primary affect the input impedance.
In A there is just a pic of transformer and a resistor and if I understand it correctly the impedance in will be 1k ohm in that specific case if nothing else is interfering.
I am not sure if Ohm's law is useful to calculate the value of the attenuator... making it a parallel resistance. If so the value of the primary impedance won't go higher that the lowest of resistances. ( I am not sure if this is how it works with impedances ... ohm's law is understood)
If it works then you should be able to use higher values of total resistance in the attenuator since the Zin is 1k and the total value of Zin will not exceed 1k???
If NOT working... How does the total value of an attenuator affect the impedance in? I am also curious about the shown attenuators how they affect the impedance since I have seen them her e and there.
I am just brainstorming with myself here so please be gentle
Best regards
/John