Well, Q5 is an emitter follower, so it does not present a significant load at the node R29/R30/C10.
Let's ignore the DC resistance of the transformer winding in the collector of Q6 for a moment.
The voltage drop over CR1 is 0.7 V, so there is 29,3 V over R29+R30.
R29=1.2M, R30=150K.
This gives a voltage of (150/1350) * 29.3V = 3.25 V.
Add the diode voltage of 0.7 Volts (CR1) and you should have +4 V on the base of Q5.
The base-emitter junctions of Q5 and Q6 each drop 0.7 V, so this would mean 4 - 1.4 = 2.6 V on the emitter of Q6.
(Or a value close to this.)
The only reason for a higher voltage on the base of Q5 could be:
- Diode CR1 reversed or defective
- Incorrect values for R29 and/or R30
- A leaky, shorted or reversed C10
- A defective Q5