No, that's wrong, dBm is related to 1mW in 600 ohms impedance.
I might as well prove this for the record.
square root of 0.001/600 = 0.001291 Amps
600 x 0.001291 = 0.77459 Volts, this is where the 0.775 VU comes from. (0dBm)
You have 1.96Vrms, so you have to divide this by 0.77459 to get to dB.
1.96/0.77459= 2.53
Then you want 20xLOG 2.53 which equals 8.06dBm.
Well done! you are bang on spec ;D
DaveP
I might as well prove this for the record.
square root of 0.001/600 = 0.001291 Amps
600 x 0.001291 = 0.77459 Volts, this is where the 0.775 VU comes from. (0dBm)
You have 1.96Vrms, so you have to divide this by 0.77459 to get to dB.
1.96/0.77459= 2.53
Then you want 20xLOG 2.53 which equals 8.06dBm.
Well done! you are bang on spec ;D
DaveP