gyraf said:Find the capacitor(s) that are switched in at the wanted position, and change those - lower value = higher freq.
gyraf said:Pultec lows are simple R/C shelving filters
gyraf said:Pultec lows are simple R/C shelving filters
Find value of capacitor in question
Calculate load resistance from your frequency-label and this capacitor value - http://www.muzique.com/schem/filter.htm
Then calculate new capacitor value based on same load resistance and wanted-frequency.
Jakob E.
gyraf said:It could be.
Also note that there are two capacitors for low, one for boost and one for cut. They are loaded differently (and hence not same value capacitor for a given frequency)
Jakob E.
gyraf said:I don't know purusha's board at all
What I mean is that at 60Hz selected, there is both a 470nF (low boost) AND a 22nf (low cut) capacitor in action. Both needs changing to new value in order to get a different frequency setting, unless you want boosting at a different freq than cutting.
Jakob E.
mitsos said:Either stick a smaller cap in parallel with each the 330nF and the 15nF in the low sections. 100nF for the boost and about 3n3 for the low cut, soldered under the board.
Or, add the extra frequency. Should be pretty easy with this version, since the switches are wired in. Just move the two 120Hz wires to the 6th switch positions, the 90Hz wires to the 5th, and add capacitors that correspond to 70Hz directly to the switch at the fourth positions, and wire the other side of the caps to the PCB. Pretty clear in the images you posted where the wires should go.
For the 1K and 10K resistors, do it like in the Gpultec schemo.
atticmike said:so you are implying that the change from 90 to 70 hz will change all the other caps as well? I just don't understand the theory behind calculating the caps for 70 hz. I just want to swap the caps of the 90 hz to a value that it equals 70 hz.
ruffrecords said:atticmike said:so you are implying that the change from 90 to 70 hz will change all the other caps as well? I just don't understand the theory behind calculating the caps for 70 hz. I just want to swap the caps of the 90 hz to a value that it equals 70 hz.
I think he was just implying you need to change two caps not just one.
The thing about the Pultec EQP1A lo boost/cut is that you can boost AND cut at the same time. So these two don't just cancel out, the frequency at which boost begins is different than it is for cut. Note that these frequencies are NOT the frequencies on the front panel switch but between 5 and ten times greater. The boost/cut happens at a rate of about 20dB per decade so to get 20dB boost at 20Hz you have to start the process of boosting at about 200Hz.
Now, in the original Pultec the ratio between the frequency on the switch and the frequencies at which boost or cut starts varies with frequency so there is no hard and fast rule. I am not sure why this is but it is probably just so they coupld use readily available component values.
Anyway, to answer your question, the boost cut is a simple RC filter so to change the frequency by 10% you simply change the capacitor by 10%. To go lower make the capacitor bigger and vice versa.
Cheers
Ian
ruffrecords said:Anyway, to answer your question, the boost cut is a simple RC filter so to change the frequency by 10% you simply change the capacitor by 10%. To go lower make the capacitor bigger and vice versa.
atticmike said:I know this might sound like a cancer in your ears but I really can't climb behind how the theory actually works and how I can determine that 70 Hz / alter the cap to get the respective band.
I appreciate all your input to help me figure it out but I was given yet only pieces of information and not a solution / approach to the problem. The only thing I could do was to approximate the issue:
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