Sounds like a DC Heater PS right? It de-ends on your setup. If you’re using a 10 VAC HEATER supply you’ll be seeing about 13 volts before the regulator.
Calculate your current draw for the LT supply. The following is just for heaters:
Each channel pulls 1/2 amp for the heaters. If you have a 10V transformer for heaters you will have about 13VDC after the rectifiers. We need to drop that down 4-5 volts to make life easy for the regulator(read, it doesn’t have a melt down).
For two channels I would parallel 2 8.2 ohm 5W radial resistors for 2a and 2b and jumper R1. This would drop volts by 5 so the reg will be happy, seeing about 9 volts.
https://www.mouser.com/ProductDetail/Ohmite/TWW5J8R2E?qs=sGAEpiMZZMtlubZbdhIBIO7UE9al6kwMwfAT6xANsRs%3d
For one channel at 1/2 an Amp I would use a 5 watt 8-10 ohm resistor in the R1 position and jumper 2a for the regulator to see 8-9 volts.
BTW, LDO voltage regulator need for this to work properly.
Note, if you are using a 300 mA power indicator lamp on the LT circuit we’’lmhave to make calculations for that, as follows.
2 channel would see 1.3 amps so 2 5W 5.6R in parallel in R2a and R2b positions will get you there. If the reg gets too hot you can add a .25-.5 Ohm 3 watt in R1 position to calm things down a half volt or so.
And 1 channel a 5W 5.1R axial will suit your needs.
Ohms law is your friend here. Hope this helps.
Calculate your current draw for the LT supply. The following is just for heaters:
Each channel pulls 1/2 amp for the heaters. If you have a 10V transformer for heaters you will have about 13VDC after the rectifiers. We need to drop that down 4-5 volts to make life easy for the regulator(read, it doesn’t have a melt down).
For two channels I would parallel 2 8.2 ohm 5W radial resistors for 2a and 2b and jumper R1. This would drop volts by 5 so the reg will be happy, seeing about 9 volts.
https://www.mouser.com/ProductDetail/Ohmite/TWW5J8R2E?qs=sGAEpiMZZMtlubZbdhIBIO7UE9al6kwMwfAT6xANsRs%3d
For one channel at 1/2 an Amp I would use a 5 watt 8-10 ohm resistor in the R1 position and jumper 2a for the regulator to see 8-9 volts.
BTW, LDO voltage regulator need for this to work properly.
Note, if you are using a 300 mA power indicator lamp on the LT circuit we’’lmhave to make calculations for that, as follows.
2 channel would see 1.3 amps so 2 5W 5.6R in parallel in R2a and R2b positions will get you there. If the reg gets too hot you can add a .25-.5 Ohm 3 watt in R1 position to calm things down a half volt or so.
And 1 channel a 5W 5.1R axial will suit your needs.
Ohms law is your friend here. Hope this helps.