plumsolly
Well-known member
the way I understand it, with a u-pad (like the ones above) the output impedance of the pad (what your monitors will see) is equal to the value of R shunt - in this case, the pot. So with a 1k pot, the output impedance of the pad will always be somewhere in between 0 (full attenuation) and 1k (full volume). The input impedance of the pad (what your source will see) is equal to R series (in the JLM schemo, 1k + 1k = 2k) plus R shunt. So in the JLM schemo, the input impedance of the pad will always be somewhere in between 2k (full attenuation) and 3k (full volume).
i think this is right, but i just learned it over the past couple of days at http://www.uneeda-audio.com/pads/ - hopefully someone will correct me if i dont understand it right - Ben
i think this is right, but i just learned it over the past couple of days at http://www.uneeda-audio.com/pads/ - hopefully someone will correct me if i dont understand it right - Ben