Hello, everyone,

I found buried in the GDIY posts where someone offered a formula for doing stepped log pots. Since I am building a mastering version D-AOC, I thought I would repost that here with my findings for position values for 100k and 500k log on a 24 position switch.

First here is the formula:

(Position number/Total number of positions)^3.3 * Potentiometer Value

Here is what I found for resistance values per each step 1-24. The values represent the math and not the resistor values that fit within a decade, etc., so you'll have to figure out what is close enough based on what is available or what you have on hand, which is what I did. Also, I started with position 1 being whatever worked out in the formula, so if you want the first step to be shorted to the pole, then you'll have to decide if you want to follow the scale or make your own adjustment(s) to based on how you decide to do your switch layout. Now, on to the numbers....

**100k:**

1. 3

2. 25

3. 77

4. 166

5. 295

6. 468

7. 685

8. 952

9. 1269

10. 1638

11. 2061

12. 2541

13. 3078

14. 3673

15. 4328

16. 5046

17. 5826

18. 6670

19. 7580

20. 8554

21. 9597

22. 10207

23. 11888

24. 13137

**500k:**

1. 13.94

2. 123.36

3. 386

4. 828.7

5. 1472

6. 2330

7. 3418

8. 4746

9. 6327

10. 8169

11. 10281

12. 12670

13. 15347

14. 18317

15. 21587

16. 25164

17. 29053

18. 33263

19. 37795

20. 42659

21. 47857

22. 53397

23. 59280

24. 65516

I hope this helps.

Thanks!

Paul