It appears that the 1968 schematic illustrates the A-10 (input tranny) primary labeling inverted - with tranny pin 6 hot. Older schematics as well as photos of reissue units illustrate tranny pin 1 hot.
If I'm correct, then this is the way to wire the input for XLR pin 2 hot:
XLR input pin 2 --> barrier strip terminal 1 (optional) --> HA100X/A10 tranny pin 1 (primary) HOT input to tranny
XLR input pin 3 --> barrier strip terminal 5 (optional) --> HA100X/A10 tranny pin 6 (primary)
(My layout reflects this, and this supports the reissue manual's instructions to use barrier strip terminal 1 for hot)
Now, the output side is always illustrated the same way in all the schematics (without the XLR) - barrier strip terminal 10 to tranny output pin 1 hot. However, photos of the reissues (with XLR's) indicate that XLR pin 2 is wired to barrier strip 8 (pin 6 of the output transformer), which would reverse the polarity from the output tranny.
This is how (in photos) the reissue unit's output is wired for XLR pin 2 hot:
XLR output pin 2 --> barrier strip terminal 8 (optional) --> A24 tranny pin 6 (secondary)
XLR output pin 3 --> barrier strip terminal 0 (optional) --> A24 tranny pin 1 (secondary) HOT output from tranny
(My layout reflects this too, and this also supports the reissue manual's instructions to use barrier strip terminal 8 for hot)
But, the trouble here is that pin 6 of the output tranny secondary is not the hot side.
Has the signal's polarity been flipped by the time it gets to the output transformer primary, so that reversing the XLR connections puts the signal back in phase on the way out?
If so, then it makes sense.