It's a long time I haven't checked this patent, so from my memory, the principle is that the voltage at pins 2 and 3 of the XLR are measured, which in turn controls the voltage upstream of the 6.8k resistors. This is a NFB process; since it tends to maintain the voltage constant irrelevant of current draw, it's a low resistance source now.analogguru said:Hmmm.... sorry, but I am unable to spot a constant voltage (source) [seen at the microphone] as there are - referring to the schematic posted above - these two 6k8 resistors which transform every voltage into a current.... even when the supply voltage is variable it stays a (variable) current source - at least this is what I have learned in school....
E.G. let's assume the mic draws 2mA -1mA per leg- the voltage drop across a 6.8k resistor is precisely 6.8V, so the system will set the voltage before the resistors at 54.8V.
Now, regarding these assertions
"..... the A-52 provides the following outstanding features:
• Safely and effectively accommodates dc-supply inputs ranging from +7 .5 volts minimum to +60 volts maximum.
• Automatically adjusts itself to power a 12-volt microphone only with any dc input from +7 .5 to just below +50 volts .
• Automatically adjusts itself to power a 12-volt or 48-volt microphone with any dc input from +50 to +60 volts.
• Acts as a regulator with any dc input above +13 volts; the dc source itself need not be inherently well regulated."
I think they must be taken with a pinch of whatever, since it's a current source. As I said, injecting 3.2mA in a mic that draws 1mA in normal operating conditions is not an ideal situation. Something has to give up; in that case the voltage on the XLR pins is higher than it would be with 6.8k resistors. Is it a problem? It depends on the rest of the circuit.
Just the same, if the microphone is designed to draw more than 3.2mA, the resulting voltage at pins 2 and 3 will be lower than expected, which may or may not have consequences.
P48 standard specifically requests 6.8k resistors: a constant-current system does not confirm to standard, neither a constant-voltage.
I'm not advocating the "True Phantom" system; I'm just saying it's a brilliant idea that solves a problem for which nobody asked a solution.