OTAs are current output devices. The input LTP (long tail pair AKA input differential pair) converts a small input voltage to current,
Correct. That is precisely what I wrote colloqially.
the OTA bias current scales or multiplies that output current proportionately.
The Bias control is not an essential feature of an OTA, equally if a bias control is applied to a classic voltage output Op-Amp (O (no T) A) we also have a VCA.
This relationship has been exploited to make current controlled variable gain stages.
This is not an inherent function of "OTA" but strictly of some specific OTA's.
It is not that trivial... The junior semiconductor engineer I was working with also thought it was trivial
![Unsure :unsure: :unsure:](data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7)
. Since OTAs are only linear over a low mV input voltage range, so the input LTP needs to be very low noise.
Yes. TBH, pressing the CA3094 into VCA service seems suboptimal.
I can think of a range of possible limiter options (including real VCA's) that have better performance.
Further to prevent control feed through the input LTP must be very well matched. At Peavey we used a house number OTA that was selected for guaranteed low control feedthrough (important when used in a power amp input stage).
You used Intersil CA3094. Selected, who knows. Normally single chip LTP's are well matched and noise is just a question of chip area. I'm not really a Chip Designer and University is ages ago, so I am not that up to speed.
When I tried to explain to the wet behind the ears junior semiconductor engineer that the OTA input LPT needed to dedicate enough silicon area to be low noise, "and" insure matching to prevent control feedthrough, I suggested perhaps paralleling multiple devices but he said not neccesary, he'd just use degeneration resistors to reduce the differential's sensitivity to DC matching. Clearly he did not understand how OTAs work, resistors in series with the input differential emitters would interfere with proper OTA operation. I decided it was not my job to teach the junior semiconductor engineer how to design ICs.
I decided that when I had a department of "singing pigs" (* see below) I sadly had to tech them how to sing at least a single note, to give me the result I required.
Now you want to instruct me about how DDT works? Since Peavey has incorporated DDT into almost every amplifier they made, there are millions of these out in the wild. Probably several different implementations but the typical one that comes to mind uses an input resistor feeding a high impedance non-inverting input. The OTA is configured to suck an opposite polarity current from that resistor at the + input node. Unlike a VCA this OTA is completely out of the circuit until active and reducing gain, so clean and quiet.
Yes, I had a look before I wrote what I wrote. Quite obvious, if you what hides behind the relabelled IC.
A VCA can do the same. Set the VCA to "maximum attenuation" as default, take the voltage output to be opposite polarity and sum it into the signal. If inactive we are pretty much looking at a static resistor.
So the OTA is still a form of VCA. Input signal goes via an attenuator. From a buffer amp. There is a series resistor to mix OTA current output and the input voltage. One could also use a Voltage output VCA and a resistor to do the mixing. Same result.
It is inverted and variable with the bias input. No-Clipping it is set to maximum attenuation, which incidentally is NOT infinity, so the OTA/VCA is ALWAYS IN CIRUIT.
With clipping the gain is turned up and the output current rises and creates a voltage across the input resistor that reduced the amplifier input.
There are many other gain control elements that can be used in a functionally equivalent circuit (and may perform better - how much this matters with the amp near clipping I think is academic).
No... While I wasn't around when the very first CS800 was released back several decades ago, the ones I was familiar with (since the mid 80s) were all class AB, and used full complementary (motorola) power output transistors. Peavey established the class A current with special diodes in a bias string that were engineered to track the temperature coefficient of the output devices.These diodes were thermally coupled to the heat sinks.
Not possible. There are (CS-1200X) six diodes and no additional resistors. And six BJT Junctions and emitter resistors. The result is pretty much zero bias in the output transistors. That is how electronics work. While all transistors biased by this chain are on the heatsink, there is still a temperature gradient.
Running at essentially zero Bias is class B, not AB.
Perhaps you encountered some counterfeit CS800s? I've heard of and seen pictures from China, and South America (I remember one that spelled Peavey wrong). The CS800 was iconic.
Yes. And the ones I had were quasi complementary.
And essentially Class B. The schematic states 0V across the Output Transistor Emitter Resistors and 0.5V base voltage
QED.
Later versions may differ.
This stopped being interesting (to me) a while ago...
Same here. However you insist making false claims, that I do not feel I can leave standing as you make them.
For stuff that happend in the 70's and 80's I usually append "IIRC - If I Remember Correctly" as my memory ain't what it used to be.
Thor