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[quote author="ToobieSnack"]Xvlk these are the pcm files you requested [/quote]
Thanks, Tobbie, nice frequency characteristic.
But some comments on noise figure .
In my editor I can see FFT picture of your record.
Some -80 dB bellow 0. How to iterpret it ???
80 - 10*log10(4096) - 10*log10(1.5)
where 4096 is number of FFT points and 1.5 is Hamming windows equivallent noise bandwidth.
Result is 80 -36.1 - 1.8 = 42.1 dB It may be usable for shellac disc records or magnetophone casette, but not for CDs.
This is my record recorded by two chineese ribbons (arranged as Blumlein pair) and followed by my own developed preamp directly to CD recorder. It is excerpt from live recording in gothic style church.
http://www.rudolfinea.cz/hanka.wav
I mean, that my record may be good for LP manufacturing, but for CD
it is rather noisy.
Computing... It is distant recording (some 5 meters in front of solist) and it is still 16 dB better than your 3 feet distance.
Yes, chineese microphones have some 6 dB worse noise parameters than
perfect large-ribbon microphines, but still better.
You may firstly determine, where is problem. The best will be to do some measurements, what is dominant source of noise.
In well developed ribbon mic recording system dominant noise source
MUST be ribbon resistance.
Trace your system with resistors bridged by tin wires.
Solder resistor with appropriate resistance and tin bridge to the system like dummy microphon, dummy ribbon, etc.
Record sample and then split tin wire (during record).
If you measure noise level (i.e. via FFT, to ommit spurious frequencies)
then you must compute equivallent noise resistance in the point
like Ap=10*log10(1+R/Rn) ,
where Ap is differency between noise levels, R is connected resistance and
Rn is equivallent noise resistance.
If you are somewhere Rn close to R, you have 3dB noise figure in this point. All points before will be worse.
Best regards,
xvlk
Thanks, Tobbie, nice frequency characteristic.
But some comments on noise figure .
In my editor I can see FFT picture of your record.
Some -80 dB bellow 0. How to iterpret it ???
80 - 10*log10(4096) - 10*log10(1.5)
where 4096 is number of FFT points and 1.5 is Hamming windows equivallent noise bandwidth.
Result is 80 -36.1 - 1.8 = 42.1 dB It may be usable for shellac disc records or magnetophone casette, but not for CDs.
This is my record recorded by two chineese ribbons (arranged as Blumlein pair) and followed by my own developed preamp directly to CD recorder. It is excerpt from live recording in gothic style church.
http://www.rudolfinea.cz/hanka.wav
I mean, that my record may be good for LP manufacturing, but for CD
it is rather noisy.
Computing... It is distant recording (some 5 meters in front of solist) and it is still 16 dB better than your 3 feet distance.
Yes, chineese microphones have some 6 dB worse noise parameters than
perfect large-ribbon microphines, but still better.
You may firstly determine, where is problem. The best will be to do some measurements, what is dominant source of noise.
In well developed ribbon mic recording system dominant noise source
MUST be ribbon resistance.
Trace your system with resistors bridged by tin wires.
Solder resistor with appropriate resistance and tin bridge to the system like dummy microphon, dummy ribbon, etc.
Record sample and then split tin wire (during record).
If you measure noise level (i.e. via FFT, to ommit spurious frequencies)
then you must compute equivallent noise resistance in the point
like Ap=10*log10(1+R/Rn) ,
where Ap is differency between noise levels, R is connected resistance and
Rn is equivallent noise resistance.
If you are somewhere Rn close to R, you have 3dB noise figure in this point. All points before will be worse.
Best regards,
xvlk