bcarso
Well-known member
The (possibly good) reason for using more transistors is series noise reduction, that is, lower equivalent input voltage noise. But to get the benefits you generally have to run more current through the total of them. With the same current density per transistor the voltage noise will go down as the square root of the number of devices. But at some point the parallel noise, or current noise, flowing in the source impedance and the feedback network components, will counteract the improvement due to lower voltage noise. The inflection point is where the source resistance is equal to the equiv. input voltage noise divided by the input current noise at a given frequency, which is known as the optimal source resistance. At this value of source resistance the contribution from noise voltage and noise current are equal.
Also, at some point, the impedance of the gain-determining R's will start to limit the noise reduction---dominated by the thermal noise of the small one at high gains. And then as you reduce those you may start to tax the ability of the op amps to drive the feedback network (less of a problem at high gain, which is where you are more concerned about noise anyway).
As I mentioned a while back I think, your input impedance will hold up for a while because of feedback. If there were no feedback it would be another story.
Also, at some point, the impedance of the gain-determining R's will start to limit the noise reduction---dominated by the thermal noise of the small one at high gains. And then as you reduce those you may start to tax the ability of the op amps to drive the feedback network (less of a problem at high gain, which is where you are more concerned about noise anyway).
As I mentioned a while back I think, your input impedance will hold up for a while because of feedback. If there were no feedback it would be another story.