ok. two (make that three) more newbie questions just to freshen up my brains:
Is this a typo? Should it say ...we apply 10 mV...?
Gm is Ic/(kT/q), right? Or, 3/25 = 0.12 (at room temperature)
or am I completely lost?
It's clear to me now how this thing works with diffmode signals, but how about common mode signals. Here, the tail resistors play a role, right?
Thank you for your help once again!
/stu
...we apply 1mV. we get 10mV/100Ω= 0.1mA emitter current...
Is this a typo? Should it say ...we apply 10 mV...?
if the transistors are biased at 3mA, then 1/Gm is about 10Ω each
Gm is Ic/(kT/q), right? Or, 3/25 = 0.12 (at room temperature)
or am I completely lost?
That's just one kind of differential amplifier, sometimes called "long tail". It is an especially handy form, so we see it more than all others put together, at least when we are not doing something fancy.
...
Generally the presence of (one or two) tail-paths does not affect the signal gain. The between-Emitters resistor is much smaller than the tail-resistors so it dominates the gain equation.
It's clear to me now how this thing works with diffmode signals, but how about common mode signals. Here, the tail resistors play a role, right?
Thank you for your help once again!
/stu