mid/side chain question?

GroupDIY Audio Forum

Help Support GroupDIY Audio Forum:

This site may earn a commission from merchant affiliate links, including eBay, Amazon, and others.

leanlowkey

Member
Joined
Sep 15, 2023
Messages
19
Location
chicago
if I have a eq that has a M/S option to it. im curious if everything else I plug into the hardware chain after that unit is also in mid side or would you need all units to have mid side to keep it into mid side for the whole chain?

thanks
 
M/S as a process has an encode and decode step. Almost always a piece of hardware that has a M/S option will switch in an encoder at the beginning and decoder at the end, so it comes back out the other end as stereo.

If you want M/S processing across multiple pieces of hardware, consider building an encoder/decoder, so you can patch in whatever chain you want. There’s a simple one here:

https://ka-electronics.com/shop/index.php?route=product/product&path=64&product_id=117
 
M/S as a process has an encode and decode step. Almost always a piece of hardware that has a M/S option will switch in an encoder at the beginning and decoder at the end, so it comes back out the other end as stereo.

If you want M/S processing across multiple pieces of hardware, consider building an encoder/decoder, so you can patch in whatever chain you want. There’s a simple one here:

https://ka-electronics.com/shop/index.php?route=product/product&path=64&product_id=117
so is that something you would plug your "whole" chain into. so that would be your last piece of gear and everything before it would now be mid/side?
 
so is that something you would plug your "whole" chain into. so that would be your last piece of gear and everything before it would now be mid/side?

It would have an input, an output, and a send and return.

Something like:
Signal in -> M/S encode -> send -> to whatever pieces of gear you want to process with M/S -> return -> M/S decode -> signal out

So it’s like an effects loop. You get a stereo signal on the output, but anything inside the loop will have been processed as M/S rather than L/R.
 

Latest posts

Back
Top