pstamler
Well-known member
[quote author="PRR"]> Disagree. 5532 offset is low enough it "should" not be a problem. That input cap is for protection against leaky consumer outputs. They are now rare, and I agree it isn't usually necessary to DC-block the input. I just think it is good practice to defend against the unexpected. Sure, for quick/cheap work, leave out the cap and see if it is a problem. [/quote]
Good point, but it should probably be something like 1µF if the circuit is to be good down to 20Hz.
No, I meant 100 ohms from the output pin to the feedback takeoff point, then 47k || 10pF for the feedback network, and the resistors to the output coming from the same point (junction between 100 ohm resistor and feedback network). My experience has been that the 100 ohm resistor adds to stability, at least with 553x and OPAx604 chips. YMMV, obviously, but that's been the case for me.
Peace,
Paul
Good point, but it should probably be something like 1µF if the circuit is to be good down to 20Hz.
> Insert a 100 ohm resistor in series with the opamp output, before the feedback resistor takeoff point (more stability).
I don't understand. Resistance between opamp output and feedback takeoff usually degrades stability. If you mean to take the 10pFd cap from opamp pin, resistor feedback after the 100Ω, that's not clear. And using couple-hundred ohm output resistors, keeping all else (including good supply bypassing) tight to the opamp, is usually plenty stable.
No, I meant 100 ohms from the output pin to the feedback takeoff point, then 47k || 10pF for the feedback network, and the resistors to the output coming from the same point (junction between 100 ohm resistor and feedback network). My experience has been that the 100 ohm resistor adds to stability, at least with 553x and OPAx604 chips. YMMV, obviously, but that's been the case for me.
Peace,
Paul